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3x^2+24x=-58
We move all terms to the left:
3x^2+24x-(-58)=0
We add all the numbers together, and all the variables
3x^2+24x+58=0
a = 3; b = 24; c = +58;
Δ = b2-4ac
Δ = 242-4·3·58
Δ = -120
Delta is less than zero, so there is no solution for the equation
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